循序渐进51study之实例8

;实例8
              include sdo_h
intsum.value  equ   40h           ;int0中断次数 max=255
intbcd1.value equ   41h
intbcd2.value equ   42h
intbcd3.value equ   43h
              org   0000h
              ljmp  start

              org   0003h
              push  acc
              push  dph
              push  dpl
              inc   intsum.value
              mov   a,intsum.value
              mov   b,#100
              div   ab
              mov   intbcd1.value,a
              mov   a,b
              mov   b,#10
              div   ab
              mov   intbcd2.value,a
              mov   intbcd3.value,b
              mov   dptr,#dispcode
              mov   a,intbcd1.value
              movc  a,@a+dptr
              mov   35h,a
              mov   a,intbcd2.value
              movc  a,@a+dptr
              mov   36h,a
              mov   a,intbcd3.value
              movc  a,@a+dptr
              mov   37h,a
              pop   dpl
              pop   dph
              pop   acc
              reti

start:        mov   sp,#70h
              setb  it0
              setb  ex0
              setb  ea
              lcall screen_clear<>
              mov   30h,#30h
              mov   31h,#37h
              mov   32h,#31h
              mov   33h,#3fh
main:         lcall print10ms<>
              sjmp  main

dispcode:     db 3fh,06h,5bh,4fh,66h,6dh,7dh,07h,7fh,67h 
              end